In Figure 1, an example is shown of how the different layers have to be manipulated to construct the edges in their entireties.

If you are familiar with the notation of a classic 3x3x3 Rubik's Cube then you must know that this affects only the outer layers of the puzzle. There are no parities on odd layered cubes due to their defined centres (in the same way a 3x3 doesn’t have parities), so there is nothing different about the 3x3 stage on a 5x5 and a normal 3x3 Rubik’s Cube (other than of course the size). There aren’t any awkward cases, and if two edges aren’t opposite one another as shown in Figure 6 (this is shown in Figure 7, where the leftmost green edge pairs with the rightmost red edge) then you can just do the flipping algorithm on one of the edges to positon them then perform the above combination of moves to solve it.In this case, the correct set of moves would be R U’ R’ which places the solved edge in the top layer and preserves the centre positions). If you have an OLL case with either one or three edges oriented correctly, then you have parity (odd number of edges oriented = odd number flipped, an impossible position on a standard Rubik’s Cube). Last two centres – Use commutators and puzzle knowledge to solve one of the last two centres, leaving the last centre solved. If you can solve the 4x4x4 and the 5x5x5 cubes then you can complete any size, even the 22x22x22 cube or the record-breaking 33x33x33!

The odd layered edge pairing system is very similar to that of the 4x4 edge pairing, but on a larger scale. After you’ve completed all eight of the first edges (shown in Figure 4), you need to solve the last four edges.

Remember – Because you’re solving an even layered cube, this means that there is no single centre piece.